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The obvious and easiest answer of course is to put the button at the top of the menu, but for design sake, I hate to have to do that. |
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I posted this in the FW forum as well, but thought it may find a solution here as it's in Dreamweaver that I need help: I have an issue where a popup menu is fairly long and the last item in that menu has a submenu that also is quite a bit long. the problem is that on 800x600 res screens, the sub-menu is all but cutoff on screen as it drops below the bottom edge of the broswer. This isn't a problem when the user has a scroll mouse, but for those people withough scroll wheels, the only way to get to those lower buttons is to scroll the window with the scroll bar, the come back to the menus and try again. I used a javascript scroll onmouseover to bump the page a bit when they mouseover the main button. That helps a bit. I need a way to either: A. add the same scroll function to the onmouseover for the submenu button B. reposition just that last submenu so that instead of down and to the right, it shows up with its bottom edge aligned with the bottom of it's parent button and builds up. For A, I need to know where to find the root code that controls that button. Is it in the JS file somewhere? How/where can add a onmouseover for that menu item For B: I see in the code where the position of the menu is defined, but for some reason, I can't change only that submenu's position. I change the numbers but it doesn't change the position of the menu. Do all of the submenus have to be positioned in the same coordinates relative to the parent button? The obvious and easiest answer of course is to put the button at the top of the menu, but for design sake, I hate to have to do that. Thanks for any help! Bryce |
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