jumpmenu

Hi,

I have a jump menu being populated dynamicly with a * query and the code
below is what i use on the jumpmenu.

<select name="menu1" onchange="MM_jumpMenu('parent',this,0)">
<?php
do {
?>
<option value="phonedetails.php?Id=<?php echo
$row_Recordset1['Id']?>"><?php echo $row_Recordset1['model']?></option>
<?php
} while ($row_Recordset1 = mysql_fetch_assoc($Recordset1));
$rows = mysql_num_rows($Recordset1);
if($rows > 0) {
mysql_data_seek($Recordset1, 0);
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
}
?>
</select>
</form>


this works fine and goes to phonedetails.php and displays that models details.

im trying to get this to happen all on the same page and the jump menu to
show the current phone model thats on the page selected.

instead of going back and forth to select different models.

hope someone can can help......or point me in the right direction.

thanks

You have to change the value to $PHP_SELF, (or the current file name)

But don't forget that your solution works only with javascript enabled
web browsers and without real links a search engine spider will stop
here.


--

gr. Olaf
PHP classes and scripts: http://www.finalwebsites.com