Dobie wrote:
Quote:
I need to know if there's a Math.object that will
make a # such as 123.4567 and round it to the
nearest 1/100. To make the # be 123.46. I have
seen Math.floor, Math.round, Math.random and
other objects. But none will do what I need.
Help ???
The only reason I need to do this is because I have
a list of products with their prices. And when you
enter the quantity amount, that # gets multiplied
by the price. And on some of the prices, a long
integer gets returned. And it would be nice to have
a price of $123.46 instead of $123.4567.
TIA,
Dobie |
Best is to always try to find answers by yourself in documentation and
references or in archives posts and threads of this newsgroup. Your
question was answered before. There is a FAQENTRY on this
http://jibbering.com/faq/#FAQ4_6
Also:
toPrecision([precision])
Parameters: precision
An integer specifying the number of digits after the decimal point.
http://devedge.netscape.com/library/...r.html#1201389
toFixed
Returns a string representing the Number object in fixed-point notation.
Syntax
toFixed([fractionDigits])
Parameters
fractionDigits
An integer specifying the number of digits after the decimal point.
Defaults to zero.
http://devedge.netscape.com/library/...r.html#1200964
DU
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